3.1670 \(\int \frac {(d+e x)^{3/2}}{(a^2+2 a b x+b^2 x^2)^3} \, dx\)

Optimal. Leaf size=208 \[ \frac {3 e^5 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{128 b^{5/2} (b d-a e)^{7/2}}-\frac {3 e^4 \sqrt {d+e x}}{128 b^2 (a+b x) (b d-a e)^3}+\frac {e^3 \sqrt {d+e x}}{64 b^2 (a+b x)^2 (b d-a e)^2}-\frac {e^2 \sqrt {d+e x}}{80 b^2 (a+b x)^3 (b d-a e)}-\frac {3 e \sqrt {d+e x}}{40 b^2 (a+b x)^4}-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5} \]

[Out]

-1/5*(e*x+d)^(3/2)/b/(b*x+a)^5+3/128*e^5*arctanh(b^(1/2)*(e*x+d)^(1/2)/(-a*e+b*d)^(1/2))/b^(5/2)/(-a*e+b*d)^(7
/2)-3/40*e*(e*x+d)^(1/2)/b^2/(b*x+a)^4-1/80*e^2*(e*x+d)^(1/2)/b^2/(-a*e+b*d)/(b*x+a)^3+1/64*e^3*(e*x+d)^(1/2)/
b^2/(-a*e+b*d)^2/(b*x+a)^2-3/128*e^4*(e*x+d)^(1/2)/b^2/(-a*e+b*d)^3/(b*x+a)

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Rubi [A]  time = 0.12, antiderivative size = 208, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {27, 47, 51, 63, 208} \[ -\frac {3 e^4 \sqrt {d+e x}}{128 b^2 (a+b x) (b d-a e)^3}+\frac {e^3 \sqrt {d+e x}}{64 b^2 (a+b x)^2 (b d-a e)^2}-\frac {e^2 \sqrt {d+e x}}{80 b^2 (a+b x)^3 (b d-a e)}+\frac {3 e^5 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{128 b^{5/2} (b d-a e)^{7/2}}-\frac {3 e \sqrt {d+e x}}{40 b^2 (a+b x)^4}-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5} \]

Antiderivative was successfully verified.

[In]

Int[(d + e*x)^(3/2)/(a^2 + 2*a*b*x + b^2*x^2)^3,x]

[Out]

(-3*e*Sqrt[d + e*x])/(40*b^2*(a + b*x)^4) - (e^2*Sqrt[d + e*x])/(80*b^2*(b*d - a*e)*(a + b*x)^3) + (e^3*Sqrt[d
+ e*x])/(64*b^2*(b*d - a*e)^2*(a + b*x)^2) - (3*e^4*Sqrt[d + e*x])/(128*b^2*(b*d - a*e)^3*(a + b*x)) - (d + e
*x)^(3/2)/(5*b*(a + b*x)^5) + (3*e^5*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b*d - a*e]])/(128*b^(5/2)*(b*d - a*e
)^(7/2))

Rule 27

Int[(u_.)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[u*Cancel[(b/2 + c*x)^(2*p)/c^p], x] /; Fr
eeQ[{a, b, c}, x] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + 1)), x] - Dist[(d*n)/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin {align*} \int \frac {(d+e x)^{3/2}}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx &=\int \frac {(d+e x)^{3/2}}{(a+b x)^6} \, dx\\ &=-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5}+\frac {(3 e) \int \frac {\sqrt {d+e x}}{(a+b x)^5} \, dx}{10 b}\\ &=-\frac {3 e \sqrt {d+e x}}{40 b^2 (a+b x)^4}-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5}+\frac {\left (3 e^2\right ) \int \frac {1}{(a+b x)^4 \sqrt {d+e x}} \, dx}{80 b^2}\\ &=-\frac {3 e \sqrt {d+e x}}{40 b^2 (a+b x)^4}-\frac {e^2 \sqrt {d+e x}}{80 b^2 (b d-a e) (a+b x)^3}-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5}-\frac {e^3 \int \frac {1}{(a+b x)^3 \sqrt {d+e x}} \, dx}{32 b^2 (b d-a e)}\\ &=-\frac {3 e \sqrt {d+e x}}{40 b^2 (a+b x)^4}-\frac {e^2 \sqrt {d+e x}}{80 b^2 (b d-a e) (a+b x)^3}+\frac {e^3 \sqrt {d+e x}}{64 b^2 (b d-a e)^2 (a+b x)^2}-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5}+\frac {\left (3 e^4\right ) \int \frac {1}{(a+b x)^2 \sqrt {d+e x}} \, dx}{128 b^2 (b d-a e)^2}\\ &=-\frac {3 e \sqrt {d+e x}}{40 b^2 (a+b x)^4}-\frac {e^2 \sqrt {d+e x}}{80 b^2 (b d-a e) (a+b x)^3}+\frac {e^3 \sqrt {d+e x}}{64 b^2 (b d-a e)^2 (a+b x)^2}-\frac {3 e^4 \sqrt {d+e x}}{128 b^2 (b d-a e)^3 (a+b x)}-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5}-\frac {\left (3 e^5\right ) \int \frac {1}{(a+b x) \sqrt {d+e x}} \, dx}{256 b^2 (b d-a e)^3}\\ &=-\frac {3 e \sqrt {d+e x}}{40 b^2 (a+b x)^4}-\frac {e^2 \sqrt {d+e x}}{80 b^2 (b d-a e) (a+b x)^3}+\frac {e^3 \sqrt {d+e x}}{64 b^2 (b d-a e)^2 (a+b x)^2}-\frac {3 e^4 \sqrt {d+e x}}{128 b^2 (b d-a e)^3 (a+b x)}-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5}-\frac {\left (3 e^4\right ) \operatorname {Subst}\left (\int \frac {1}{a-\frac {b d}{e}+\frac {b x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{128 b^2 (b d-a e)^3}\\ &=-\frac {3 e \sqrt {d+e x}}{40 b^2 (a+b x)^4}-\frac {e^2 \sqrt {d+e x}}{80 b^2 (b d-a e) (a+b x)^3}+\frac {e^3 \sqrt {d+e x}}{64 b^2 (b d-a e)^2 (a+b x)^2}-\frac {3 e^4 \sqrt {d+e x}}{128 b^2 (b d-a e)^3 (a+b x)}-\frac {(d+e x)^{3/2}}{5 b (a+b x)^5}+\frac {3 e^5 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{128 b^{5/2} (b d-a e)^{7/2}}\\ \end {align*}

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Mathematica [C]  time = 0.02, size = 52, normalized size = 0.25 \[ \frac {2 e^5 (d+e x)^{5/2} \, _2F_1\left (\frac {5}{2},6;\frac {7}{2};-\frac {b (d+e x)}{a e-b d}\right )}{5 (a e-b d)^6} \]

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x)^(3/2)/(a^2 + 2*a*b*x + b^2*x^2)^3,x]

[Out]

(2*e^5*(d + e*x)^(5/2)*Hypergeometric2F1[5/2, 6, 7/2, -((b*(d + e*x))/(-(b*d) + a*e))])/(5*(-(b*d) + a*e)^6)

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fricas [B]  time = 1.14, size = 1492, normalized size = 7.17 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)/(b^2*x^2+2*a*b*x+a^2)^3,x, algorithm="fricas")

[Out]

[-1/1280*(15*(b^5*e^5*x^5 + 5*a*b^4*e^5*x^4 + 10*a^2*b^3*e^5*x^3 + 10*a^3*b^2*e^5*x^2 + 5*a^4*b*e^5*x + a^5*e^
5)*sqrt(b^2*d - a*b*e)*log((b*e*x + 2*b*d - a*e - 2*sqrt(b^2*d - a*b*e)*sqrt(e*x + d))/(b*x + a)) + 2*(128*b^6
*d^5 - 464*a*b^5*d^4*e + 584*a^2*b^4*d^3*e^2 - 258*a^3*b^3*d^2*e^3 - 5*a^4*b^2*d*e^4 + 15*a^5*b*e^5 + 15*(b^6*
d*e^4 - a*b^5*e^5)*x^4 - 10*(b^6*d^2*e^3 - 8*a*b^5*d*e^4 + 7*a^2*b^4*e^5)*x^3 + 2*(4*b^6*d^3*e^2 - 27*a*b^5*d^
2*e^3 + 87*a^2*b^4*d*e^4 - 64*a^3*b^3*e^5)*x^2 + 2*(88*b^6*d^4*e - 344*a*b^5*d^3*e^2 + 489*a^2*b^4*d^2*e^3 - 2
68*a^3*b^3*d*e^4 + 35*a^4*b^2*e^5)*x)*sqrt(e*x + d))/(a^5*b^7*d^4 - 4*a^6*b^6*d^3*e + 6*a^7*b^5*d^2*e^2 - 4*a^
8*b^4*d*e^3 + a^9*b^3*e^4 + (b^12*d^4 - 4*a*b^11*d^3*e + 6*a^2*b^10*d^2*e^2 - 4*a^3*b^9*d*e^3 + a^4*b^8*e^4)*x
^5 + 5*(a*b^11*d^4 - 4*a^2*b^10*d^3*e + 6*a^3*b^9*d^2*e^2 - 4*a^4*b^8*d*e^3 + a^5*b^7*e^4)*x^4 + 10*(a^2*b^10*
d^4 - 4*a^3*b^9*d^3*e + 6*a^4*b^8*d^2*e^2 - 4*a^5*b^7*d*e^3 + a^6*b^6*e^4)*x^3 + 10*(a^3*b^9*d^4 - 4*a^4*b^8*d
^3*e + 6*a^5*b^7*d^2*e^2 - 4*a^6*b^6*d*e^3 + a^7*b^5*e^4)*x^2 + 5*(a^4*b^8*d^4 - 4*a^5*b^7*d^3*e + 6*a^6*b^6*d
^2*e^2 - 4*a^7*b^5*d*e^3 + a^8*b^4*e^4)*x), -1/640*(15*(b^5*e^5*x^5 + 5*a*b^4*e^5*x^4 + 10*a^2*b^3*e^5*x^3 + 1
0*a^3*b^2*e^5*x^2 + 5*a^4*b*e^5*x + a^5*e^5)*sqrt(-b^2*d + a*b*e)*arctan(sqrt(-b^2*d + a*b*e)*sqrt(e*x + d)/(b
*e*x + b*d)) + (128*b^6*d^5 - 464*a*b^5*d^4*e + 584*a^2*b^4*d^3*e^2 - 258*a^3*b^3*d^2*e^3 - 5*a^4*b^2*d*e^4 +
15*a^5*b*e^5 + 15*(b^6*d*e^4 - a*b^5*e^5)*x^4 - 10*(b^6*d^2*e^3 - 8*a*b^5*d*e^4 + 7*a^2*b^4*e^5)*x^3 + 2*(4*b^
6*d^3*e^2 - 27*a*b^5*d^2*e^3 + 87*a^2*b^4*d*e^4 - 64*a^3*b^3*e^5)*x^2 + 2*(88*b^6*d^4*e - 344*a*b^5*d^3*e^2 +
489*a^2*b^4*d^2*e^3 - 268*a^3*b^3*d*e^4 + 35*a^4*b^2*e^5)*x)*sqrt(e*x + d))/(a^5*b^7*d^4 - 4*a^6*b^6*d^3*e + 6
*a^7*b^5*d^2*e^2 - 4*a^8*b^4*d*e^3 + a^9*b^3*e^4 + (b^12*d^4 - 4*a*b^11*d^3*e + 6*a^2*b^10*d^2*e^2 - 4*a^3*b^9
*d*e^3 + a^4*b^8*e^4)*x^5 + 5*(a*b^11*d^4 - 4*a^2*b^10*d^3*e + 6*a^3*b^9*d^2*e^2 - 4*a^4*b^8*d*e^3 + a^5*b^7*e
^4)*x^4 + 10*(a^2*b^10*d^4 - 4*a^3*b^9*d^3*e + 6*a^4*b^8*d^2*e^2 - 4*a^5*b^7*d*e^3 + a^6*b^6*e^4)*x^3 + 10*(a^
3*b^9*d^4 - 4*a^4*b^8*d^3*e + 6*a^5*b^7*d^2*e^2 - 4*a^6*b^6*d*e^3 + a^7*b^5*e^4)*x^2 + 5*(a^4*b^8*d^4 - 4*a^5*
b^7*d^3*e + 6*a^6*b^6*d^2*e^2 - 4*a^7*b^5*d*e^3 + a^8*b^4*e^4)*x)]

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giac [B]  time = 0.22, size = 412, normalized size = 1.98 \[ -\frac {3 \, \arctan \left (\frac {\sqrt {x e + d} b}{\sqrt {-b^{2} d + a b e}}\right ) e^{5}}{128 \, {\left (b^{5} d^{3} - 3 \, a b^{4} d^{2} e + 3 \, a^{2} b^{3} d e^{2} - a^{3} b^{2} e^{3}\right )} \sqrt {-b^{2} d + a b e}} - \frac {15 \, {\left (x e + d\right )}^{\frac {9}{2}} b^{4} e^{5} - 70 \, {\left (x e + d\right )}^{\frac {7}{2}} b^{4} d e^{5} + 128 \, {\left (x e + d\right )}^{\frac {5}{2}} b^{4} d^{2} e^{5} + 70 \, {\left (x e + d\right )}^{\frac {3}{2}} b^{4} d^{3} e^{5} - 15 \, \sqrt {x e + d} b^{4} d^{4} e^{5} + 70 \, {\left (x e + d\right )}^{\frac {7}{2}} a b^{3} e^{6} - 256 \, {\left (x e + d\right )}^{\frac {5}{2}} a b^{3} d e^{6} - 210 \, {\left (x e + d\right )}^{\frac {3}{2}} a b^{3} d^{2} e^{6} + 60 \, \sqrt {x e + d} a b^{3} d^{3} e^{6} + 128 \, {\left (x e + d\right )}^{\frac {5}{2}} a^{2} b^{2} e^{7} + 210 \, {\left (x e + d\right )}^{\frac {3}{2}} a^{2} b^{2} d e^{7} - 90 \, \sqrt {x e + d} a^{2} b^{2} d^{2} e^{7} - 70 \, {\left (x e + d\right )}^{\frac {3}{2}} a^{3} b e^{8} + 60 \, \sqrt {x e + d} a^{3} b d e^{8} - 15 \, \sqrt {x e + d} a^{4} e^{9}}{640 \, {\left (b^{5} d^{3} - 3 \, a b^{4} d^{2} e + 3 \, a^{2} b^{3} d e^{2} - a^{3} b^{2} e^{3}\right )} {\left ({\left (x e + d\right )} b - b d + a e\right )}^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)/(b^2*x^2+2*a*b*x+a^2)^3,x, algorithm="giac")

[Out]

-3/128*arctan(sqrt(x*e + d)*b/sqrt(-b^2*d + a*b*e))*e^5/((b^5*d^3 - 3*a*b^4*d^2*e + 3*a^2*b^3*d*e^2 - a^3*b^2*
e^3)*sqrt(-b^2*d + a*b*e)) - 1/640*(15*(x*e + d)^(9/2)*b^4*e^5 - 70*(x*e + d)^(7/2)*b^4*d*e^5 + 128*(x*e + d)^
(5/2)*b^4*d^2*e^5 + 70*(x*e + d)^(3/2)*b^4*d^3*e^5 - 15*sqrt(x*e + d)*b^4*d^4*e^5 + 70*(x*e + d)^(7/2)*a*b^3*e
^6 - 256*(x*e + d)^(5/2)*a*b^3*d*e^6 - 210*(x*e + d)^(3/2)*a*b^3*d^2*e^6 + 60*sqrt(x*e + d)*a*b^3*d^3*e^6 + 12
8*(x*e + d)^(5/2)*a^2*b^2*e^7 + 210*(x*e + d)^(3/2)*a^2*b^2*d*e^7 - 90*sqrt(x*e + d)*a^2*b^2*d^2*e^7 - 70*(x*e
+ d)^(3/2)*a^3*b*e^8 + 60*sqrt(x*e + d)*a^3*b*d*e^8 - 15*sqrt(x*e + d)*a^4*e^9)/((b^5*d^3 - 3*a*b^4*d^2*e + 3
*a^2*b^3*d*e^2 - a^3*b^2*e^3)*((x*e + d)*b - b*d + a*e)^5)

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maple [A]  time = 0.06, size = 300, normalized size = 1.44 \[ \frac {3 \left (e x +d \right )^{\frac {9}{2}} b^{2} e^{5}}{128 \left (b e x +a e \right )^{5} \left (a^{3} e^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right )}+\frac {7 \left (e x +d \right )^{\frac {7}{2}} b \,e^{5}}{64 \left (b e x +a e \right )^{5} \left (a^{2} e^{2}-2 a b d e +b^{2} d^{2}\right )}-\frac {3 \sqrt {e x +d}\, a \,e^{6}}{128 \left (b e x +a e \right )^{5} b^{2}}+\frac {3 \sqrt {e x +d}\, d \,e^{5}}{128 \left (b e x +a e \right )^{5} b}+\frac {\left (e x +d \right )^{\frac {5}{2}} e^{5}}{5 \left (b e x +a e \right )^{5} \left (a e -b d \right )}-\frac {7 \left (e x +d \right )^{\frac {3}{2}} e^{5}}{64 \left (b e x +a e \right )^{5} b}+\frac {3 e^{5} \arctan \left (\frac {\sqrt {e x +d}\, b}{\sqrt {\left (a e -b d \right ) b}}\right )}{128 \left (a^{3} e^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right ) \sqrt {\left (a e -b d \right ) b}\, b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^(3/2)/(b^2*x^2+2*a*b*x+a^2)^3,x)

[Out]

3/128*e^5/(b*e*x+a*e)^5/(a^3*e^3-3*a^2*b*d*e^2+3*a*b^2*d^2*e-b^3*d^3)*b^2*(e*x+d)^(9/2)+7/64*e^5/(b*e*x+a*e)^5
*b/(a^2*e^2-2*a*b*d*e+b^2*d^2)*(e*x+d)^(7/2)+1/5*e^5/(b*e*x+a*e)^5/(a*e-b*d)*(e*x+d)^(5/2)-7/64*e^5/(b*e*x+a*e
)^5/b*(e*x+d)^(3/2)-3/128*e^6/(b*e*x+a*e)^5/b^2*(e*x+d)^(1/2)*a+3/128*e^5/(b*e*x+a*e)^5/b*(e*x+d)^(1/2)*d+3/12
8*e^5/(a^3*e^3-3*a^2*b*d*e^2+3*a*b^2*d^2*e-b^3*d^3)/b^2/((a*e-b*d)*b)^(1/2)*arctan((e*x+d)^(1/2)/((a*e-b*d)*b)
^(1/2)*b)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)/(b^2*x^2+2*a*b*x+a^2)^3,x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(a*e-b*d>0)', see `assume?` for
more details)Is a*e-b*d positive or negative?

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mupad [B]  time = 0.66, size = 398, normalized size = 1.91 \[ \frac {\frac {e^5\,{\left (d+e\,x\right )}^{5/2}}{5\,\left (a\,e-b\,d\right )}-\frac {7\,e^5\,{\left (d+e\,x\right )}^{3/2}}{64\,b}+\frac {3\,b^2\,e^5\,{\left (d+e\,x\right )}^{9/2}}{128\,{\left (a\,e-b\,d\right )}^3}-\frac {3\,e^5\,\left (a\,e-b\,d\right )\,\sqrt {d+e\,x}}{128\,b^2}+\frac {7\,b\,e^5\,{\left (d+e\,x\right )}^{7/2}}{64\,{\left (a\,e-b\,d\right )}^2}}{\left (d+e\,x\right )\,\left (5\,a^4\,b\,e^4-20\,a^3\,b^2\,d\,e^3+30\,a^2\,b^3\,d^2\,e^2-20\,a\,b^4\,d^3\,e+5\,b^5\,d^4\right )-{\left (d+e\,x\right )}^2\,\left (-10\,a^3\,b^2\,e^3+30\,a^2\,b^3\,d\,e^2-30\,a\,b^4\,d^2\,e+10\,b^5\,d^3\right )+b^5\,{\left (d+e\,x\right )}^5-\left (5\,b^5\,d-5\,a\,b^4\,e\right )\,{\left (d+e\,x\right )}^4+a^5\,e^5-b^5\,d^5+{\left (d+e\,x\right )}^3\,\left (10\,a^2\,b^3\,e^2-20\,a\,b^4\,d\,e+10\,b^5\,d^2\right )-10\,a^2\,b^3\,d^3\,e^2+10\,a^3\,b^2\,d^2\,e^3+5\,a\,b^4\,d^4\,e-5\,a^4\,b\,d\,e^4}+\frac {3\,e^5\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {d+e\,x}}{\sqrt {a\,e-b\,d}}\right )}{128\,b^{5/2}\,{\left (a\,e-b\,d\right )}^{7/2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d + e*x)^(3/2)/(a^2 + b^2*x^2 + 2*a*b*x)^3,x)

[Out]

((e^5*(d + e*x)^(5/2))/(5*(a*e - b*d)) - (7*e^5*(d + e*x)^(3/2))/(64*b) + (3*b^2*e^5*(d + e*x)^(9/2))/(128*(a*
e - b*d)^3) - (3*e^5*(a*e - b*d)*(d + e*x)^(1/2))/(128*b^2) + (7*b*e^5*(d + e*x)^(7/2))/(64*(a*e - b*d)^2))/((
d + e*x)*(5*b^5*d^4 + 5*a^4*b*e^4 - 20*a^3*b^2*d*e^3 + 30*a^2*b^3*d^2*e^2 - 20*a*b^4*d^3*e) - (d + e*x)^2*(10*
b^5*d^3 - 10*a^3*b^2*e^3 + 30*a^2*b^3*d*e^2 - 30*a*b^4*d^2*e) + b^5*(d + e*x)^5 - (5*b^5*d - 5*a*b^4*e)*(d + e
*x)^4 + a^5*e^5 - b^5*d^5 + (d + e*x)^3*(10*b^5*d^2 + 10*a^2*b^3*e^2 - 20*a*b^4*d*e) - 10*a^2*b^3*d^3*e^2 + 10
*a^3*b^2*d^2*e^3 + 5*a*b^4*d^4*e - 5*a^4*b*d*e^4) + (3*e^5*atan((b^(1/2)*(d + e*x)^(1/2))/(a*e - b*d)^(1/2)))/
(128*b^(5/2)*(a*e - b*d)^(7/2))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**(3/2)/(b**2*x**2+2*a*b*x+a**2)**3,x)

[Out]

Timed out

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